Raoult's Law Calculator
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| Mole Fraction of Solvent | 0.9 |
|---|---|
| Vapor Pressure of Pure Solvent | 23.8 mmHg |
Raoult's Law Calculator
Calculate the vapor pressure of an ideal solution and vapor-pressure lowering using Raoult's law: P = x(solvent) · P°.
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Understanding Raoult's law
Raoult's law describes how the vapor pressure of an ideal solution depends on composition. When a non-volatile solute dissolves in a liquid, the solvent's vapor pressure drops in proportion to how much solute is present. The law connects this pressure to the mole fraction of the solvent:
P=xsolvent⋅P∘where is the vapor pressure of the solution, is the mole fraction of the solvent, and is the vapor pressure of the pure solvent at the same temperature.
Vapor-pressure lowering
Because whenever any solute is present, the vapor pressure of the solution is always less than that of the pure solvent. The drop is called vapor-pressure lowering:
ΔP=P∘−P=xsolute⋅P∘Since , the lowering equals the mole fraction of solute times the pure vapor pressure. This is a colligative property — it depends only on the number of solute particles, not on their chemical identity.
| Quantity | Symbol | Relation |
|---|---|---|
| Vapor pressure of solution | ||
| Vapor pressure of pure solvent | measured or looked up | |
| Mole fraction of solvent | ||
| Vapor-pressure lowering |
Worked example
A solution is prepared by dissolving glucose () in water (). The mixture contains 18 g of glucose and 90 g of water at 25 °C, where the vapor pressure of pure water is 23.8 mmHg. Find the vapor pressure of the solution and the vapor-pressure lowering.
Step 1 — find moles:
nglucose=180 g/mol18 g=0.10 mol nwater=18 g/mol90 g=5.00 molStep 2 — find mole fraction of solvent:
xwater=nwater+nglucosenwater=5.00+0.105.00=5.105.00≈0.9804Step 3 — apply Raoult's law:
P=xwater⋅P∘=0.9804×23.8 mmHg≈23.33 mmHgStep 4 — find the lowering:
ΔP=P∘−P=23.8−23.33≈0.47 mmHgRaoult's law and other colligative properties
Vapor-pressure lowering is the starting point for three other colligative effects:
- Boiling-point elevation: a lower vapor pressure means the solution must be heated to a higher temperature before its vapor pressure reaches atmospheric pressure.
- Freezing-point depression: the reduced vapor pressure shifts the solid–liquid equilibrium, lowering the freezing point.
- Osmotic pressure: when a solution is separated from pure solvent by a semipermeable membrane, the difference in vapor pressure drives solvent across the membrane until osmotic pressure builds up to compensate.
All four effects depend on (or equivalently, on molality), not on the nature of the solute.
When Raoult's law holds — and when it does not
Raoult's law is exact for ideal solutions, in which solute–solvent interactions are the same strength as solvent–solvent interactions. In practice, the law works well for:
- Dilute solutions of non-electrolytes (sugars, urea, alcohols in a compatible solvent)
- Mixtures of structurally similar liquids (benzene and toluene)
It breaks down for concentrated solutions, for electrolytes (which release multiple ions per formula unit), and for solutes that associate or react with the solvent. For electrolytes, the effective solute particle count is increased by the van't Hoff factor , so .
Vapor pressures of common solvents at 25 °C
| Solvent | Vapor pressure (mmHg) |
|---|---|
| Water | 23.8 |
| Ethanol | 59.0 |
| Methanol | 127 |
| Acetone | 231 |
| Diethyl ether | 538 |
These values let you compute the vapor pressure of a dilute solution directly: enter the mole fraction and the pure-solvent vapor pressure from the table above.
Frequently Asked Questions (FAQ)
What is the formula for Raoult's law?
Raoult's law states that the vapor pressure of a solvent above an ideal solution equals the mole fraction of the solvent multiplied by the vapor pressure of the pure solvent: P = x(solvent) × P°. The vapor-pressure lowering is the difference ΔP = P° − P = x(solute) × P°, where x(solute) = 1 − x(solvent). For example, dissolving a solute so the solvent's mole fraction drops to 0.90 in water at 25 °C (P° = 23.8 mmHg) gives P = 0.90 × 23.8 = 21.42 mmHg and ΔP = 2.38 mmHg.
What is vapor-pressure lowering?
Vapor-pressure lowering is the decrease in a solvent's vapor pressure when a non-volatile solute dissolves in it. Solute particles occupy part of the liquid surface and reduce the rate at which solvent molecules escape into the vapor phase, so the equilibrium vapor pressure falls. The lowering ΔP = x(solute) × P° is proportional to the mole fraction of solute, not to any chemical property of the solute — it is a colligative property. This same effect underlies boiling-point elevation and freezing-point depression.
When does Raoult's law apply?
Raoult's law applies exactly to ideal solutions, in which solute–solvent interactions are identical in strength to solvent–solvent interactions. In practice, dilute solutions of non-electrolytes (sugars, alcohols, urea) in a compatible solvent come close to ideal behavior. The law breaks down for concentrated solutions, for solutes that associate or dissociate in solution, and for mixtures of liquids with strong or weak cross-interactions. For electrolytes, the effective concentration is multiplied by the van’t Hoff factor i.
What is the difference between a volatile and a non-volatile solute?
A non-volatile solute has negligible vapor pressure of its own at the temperature of interest — common examples are salts, sugars, and urea. Adding a non-volatile solute only lowers the solvent's vapor pressure, and Raoult's law gives the total vapor pressure directly as x(solvent) × P°. A volatile solute also contributes its own partial pressure to the mixture, so the total vapor pressure becomes the sum of each component's partial pressure — each component contributing its mole fraction times its own pure vapor pressure. The simple form used here assumes a non-volatile solute.
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Osmotic Pressure Calculator
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